If it's not what You are looking for type in the equation solver your own equation and let us solve it.
=-20Y^2-400Y-24
We move all terms to the left:
-(-20Y^2-400Y-24)=0
We get rid of parentheses
20Y^2+400Y+24=0
a = 20; b = 400; c = +24;
Δ = b2-4ac
Δ = 4002-4·20·24
Δ = 158080
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{158080}=\sqrt{64*2470}=\sqrt{64}*\sqrt{2470}=8\sqrt{2470}$$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(400)-8\sqrt{2470}}{2*20}=\frac{-400-8\sqrt{2470}}{40} $$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(400)+8\sqrt{2470}}{2*20}=\frac{-400+8\sqrt{2470}}{40} $
| 2x-4=4/3x+2 | | 6r+6=9 | | 78+x=3x-40 | | a÷4+3=9 | | (2x(5-x)^(2/3))-(2x^2)/(3(5-x)^(1/3))=0 | | 2(4x-2)=5x | | 28x+35=86 | | x/3-10=2/3x+5 | | 25-(x+5)=-415-(15-415) | | |x+7|.3=15 | | x+0,5x=56-0,25x | | x+1/2x=56-1/4x | | 38x+16=5(7x+3)+3x+1 | | 6y-11=4(3y-7)+2y-23 | | (-1/8)+x=5/14 | | 5/3x+1/3x=4x+39/3+7/3x | | (x+4)+(4x-19)=180 | | |3v+12|=9 | | (6x+1÷7)-(2x-7÷3)=4 | | -.5(x+4)=-8 | | 2x+75=8x+9 | | 1/2(6)+3y=4 | | (3x=2)(2x-4) | | 2p+8/3=4 | | 3(m+2)^2+16(m+2)+16=0 | | |10x-3|=|7x-2| | | 3(m+2)2+16(m+2)+16=0 | | -1(-3y+6)=6 | | 5(-3x-2)-(x-3)=-4(5x+5)+13 | | 37-4x=5x-8 | | 8+13p-4=9p+81-7p | | 31/2=z/4 |